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<small><font face="Helvetica, Arial, sans-serif">Bill,<br>
<br>
It is more that it is counterintuitive to me to be
using ((x,y,z)
-> t) rather than (t -> (x,y,z)). However, I guess the same
thing appears on the plot. The reason for reversing the order seems to
be to get the correct topology. So I now have a recipe, but I am not
sure I understand what is happening. Is it written up somewhere what
has and doesn't have a topology and what that topology is. I haven't
come across it.<br>
<br>
It is also interesting about the manifold dimension =
1. It seems
to me that the domain, which is the part that goes with the
</font></small><small><font
face="Helvetica, Arial, sans-serif">Gridded3DSet, has manifold
dimension = 3, and that it is the range that has manifold dimension
1. (When using your order.) Or am I just
confused.</font></small><br>
<small><font face="Helvetica, Arial, sans-serif"><br>
I did try to make a cursor consisting of two crossed lines
recently. I noticed that I needed to use a Gridded2DSet, whereas a
Linear2D set should have served. I believe the later gave points, not
lines. I assume this is the same problem. (I ended up using a
shape.)<br>
<br>
Thanks for the information,<br>
<br>
-Ken<br>
<br>
</font></small><br>
Bill Hibbard wrote:
<blockquote cite="mid20070327195212.528DC1BF900@xxxxxxxxxxxxxxxxxxxxxx"
type="cite">
<div>Ken,<br>
<br>
This works because the lines between points must come from<br>
a topology, and the Gridded3DSet defines a topology (a sequence<br>
of lines in the case of manifold dimension = 1). Given a FlatField<br>
with MathType (t -> (x, y, z)), the display logic should not assume<br>
a topology among the (x, y, z) range points since there are plenty<br>
of examples where there would not be any.<br>
<br>
By the way, it looks like your messages are making it to the list<br>
now so no more need to CC Tom and me. I should have told<br>
you that I use <a class="moz-txt-link-abbreviated"
href="mailto:hiding@xxxxxxxxx";>hiding@xxxxxxxxx</a> for all mailing list
traffic (I'm<br>
hiding from spammers harvesting addresses). I suspect the list<br>
server rejected your first message because the embedded image<br>
exceeded the message length limit.<br>
<br>
Cheers,<br>
Bill<br>
<br>
<blockquote
style="border-left: 2px solid rgb(16, 16, 255); margin-left: 5px;
padding-left: 5px;">-----
Original Message -----<br>
From: "Kenneth Evans" <evans@xxxxxxxxxxx><br>
To: Visad <visad@xxxxxxxxxxxxxxxx><br>
Subject: Re: Parametric Function with Lines Instead of Points<br>
Date: Tue, 27 Mar 2007 14:27:04 -0500<br>
<br>
<font size="-1"><font face="Helvetica, Arial, sans-serif">Bill,<br>
<br>
Thanks. That was easy and worked. I need
to think about why,
though.<br>
<br>
In regard to the email's not getting through: Is
it possibly
because I had a screen dump in the body, rather than as an attachment.
(I do that all the time and didn't think.)<br>
<br>
Thanks again,<br>
<br>
-Ken<br>
</font></font><br>
Bill Hibbard wrote:
</visad@xxxxxxxxxxxxxxxx></evans@xxxxxxxxxxx>
<blockquote
cite="midPine.SOC.4.64.0703271138180.22630@xxxxxxxxxxxxxxxxxxx"
type="cite">Hi Ken, <br>
<br>
<blockquote type="cite">I want to plot a function (t -> (x, y,
z)), for example, an orbit. I can do <br>
this OK, but I get points on the plot and I would like lines. Can I do
this <br>
and if so, how? It doesn't seem like it should be hard, but I haven't <br>
figured it out. <br>
</blockquote>
<br>
You can do this by using your data to construct a <br>
FlatField with MathType (((x, y, z) -> t) and whose <br>
domain Set is a Gridded3DSet with manifold dimension <br>
= 1. You should be able to find the Gridded3DSet <br>
constructor for manifold dimension = 1. <br>
<br>
If you have any follow up questions please send them <br>
to the VisAD mailing list, as you tried to do before, <br>
and hopefully they'll get through. You can CC Tom and <br>
me just to make sure. <br>
<br>
Good luck, <br>
Bill <br>
</blockquote>
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